3sin^2x-5cosx-3=2

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Solution for 3sin^2x-5cosx-3=2 equation:


Simplifying
3sin2x + -5cosx + -3 = 2

Reorder the terms:
-3 + -5cosx + 3in2sx = 2

Solving
-3 + -5cosx + 3in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -5cosx + 3 + 3in2sx = 2 + 3

Reorder the terms:
-3 + 3 + -5cosx + 3in2sx = 2 + 3

Combine like terms: -3 + 3 = 0
0 + -5cosx + 3in2sx = 2 + 3
-5cosx + 3in2sx = 2 + 3

Combine like terms: 2 + 3 = 5
-5cosx + 3in2sx = 5

Add '-3in2sx' to each side of the equation.
-5cosx + 3in2sx + -3in2sx = 5 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
-5cosx + 0 = 5 + -3in2sx
-5cosx = 5 + -3in2sx

Divide each side by '-5osx'.
c = -1o-1s-1x-1 + 0.6in2o-1

Simplifying
c = -1o-1s-1x-1 + 0.6in2o-1

Reorder the terms:
c = 0.6in2o-1 + -1o-1s-1x-1

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